fieldname__validate function

[ststoddard]

Hello, a question regarding the validate function. I attempted the following per the documentation:

Code: Select all

function location_code__validate(&$record,$value,$params) {
       $app =& Dataface_application::getInstance();
        $auth =& Dataface_AuthenticationTool::getInstance();      
       if ( $value == 'test' ) {
          $params['message'] = "no!";
          return false;
          }
}


As a test after failed attempts using a more complex validation condition. Basically, the message doesn't come through. I get the form back with the field highlighted and the message saying "Permission Denied".

Am I doing something wrong?

FYI Steve -- I had to re-register with the user forum as it wouldn't accept my old username.

[shannah]

Try passing $params by reference:

Code: Select all

function location_code__validate(&$record,$value,&$params) {
...


[inmisia]

HI,
I have same problems with:

Code: Select all

function Valore__validate( &$record, $value, &$params){
       
        if ( $value>10 or $value<0 ){
            $params['message'] = "Valore non valido.";
         return false;
        } else
      {
            return true;
        }


and pass &$params by reference.
I get this error:
Fatal error: [pear_error: message="Valore non valido." code=211 mode= level=notice prefix="" info="On line 77 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\Error.php in function printStackTrace()
On line 1447 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\QuickForm.php in function permissionDenied(Valore non valido.)

[shannah]

Yes.. this appears to be a bug. In Dataface/QuickForm.php around line 1447, you will find some code:

Code: Select all

if ( !$this->_record->validate($fieldname, $value, $params) ){
         
         return Dataface_Error::permissionDenied($params['message']);
      }


Comment this out or remove it... that should fix the issue.

[inmisia]

Hi,
I have Comment it, but now there isn't error message when field is not valid

[shannah]

OK.. I have reviewed the source and run tests on it and it appears to be working fine for me with version 0.7.1.

Please undo the changes that I suggested earlier. That code is a good failsafe.

Which leads me to ask: which version of Dataface are you running?

[inmisia]

Hi,
I'm using version 0.7.1. too, I get this error:

Fatal error: [pear_error: message="Valore non valido." code=211 mode= level=notice prefix="" info="On line 77 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\Error.php in function printStackTrace()
On line 1447 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\QuickForm.php in function permissionDenied(Valore non valido.)
On line 1320 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\QuickForm.php in function pushField(Valore)
On line 2016 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\QuickForm.php in function push()
On line of file in function save(array(28,1,15,2007-11-13,Save,2,array(2),,edit,0,analisi,0,30,browse,Record successfully saved.
,)
On line 1608 of file E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\lib\HTML\QuickForm.php in function call_user_func(array(Dataface_QuickForm Object,save),array(28,1,15,2007-11-13,Save,2,array(2),,edit,0,analisi,0,30,browse,Record successfully saved.
,)
On line in E:\Programmi\OCS Inventory NG\xampp\htdocs\dataface\Dataface\QuickForm.php on line 2046

[shannah]

Do you get this error when adding a new record, editing an existing record, or both?

[inmisia]

HI,
I get this error in both case, I'm using XAMPP per Windows Version 1.5.1
with:Apache/2.2.0 (Win32),PHP/5.1.1

I have another question about validate, is posible view a value of another fields? Example with $record->val('IDtipoAnalisi'), but I have view a value from form.

[shannah]

I can't seem to reproduce this behavior.
Stephen, can you confirm that you are still having problems with this one?

-Steve

[inmisia]

Hi, and about second question? Is it possible validate a field using
a value from other form field?

[shannah]

Absolutely.

The first parameter to your validate method &$record is a Dataface_Record object of the current record.

You can get the value of any field using $record->val('fieldname')

[inmisia]

Hi, I need to validate a field using e value on form, not in table.
Ex if validate run on insert, $record->val('fieldname') is void.

[shannah]

Oh.. yes. For this you should just use the values in the $_POST array.

e.g.

Code: Select all

if ($_POST['fieldname'] == 'somevalue'){
    // do something ...
}
else {
    // do somethine else
}



[inmisia]

Hi, was come back!!
I try with XAMPP Version 1.6.4 for Windows XP Professional service pack 2
( * Apache HTTPD 2.2.6 + Openssl 0.9.8e
* MySQL 5.0.45
* PHP 5.2.4
* PHP 4.4.7
* phpMyAdmin 2.11.1
* Zend Optimizer 3.3.0 )
and I get same error:
Fatal error: [pear_error: message="Valore non valido. range:" code=211 mode= level=notice prefix="" info="On line 77 of file C:\xampp\htdocs\dataface\Dataface\Error.php in function printStackTrace()
On line 1447 of file C:\xampp\htdocs\dataface\Dataface\QuickForm.php in function permissionDenied(Valore non valido. range:)
On line 1320 of file C:\xampp\htdocs\dataface\Dataface\QuickForm.php in function pushField(Valore)
On line 2016 of file C:\xampp\htdocs\dataface\Dataface\QuickForm.php in function push()
On line of file in function save(array(28,1,45,2007-11-05,Save,3,array(3),,edit,0,analisi,0,30,browse,-action=edit&-cursor=0&-table=a)
On line 1608 of file C:\xampp\htdocs\dataface\lib\HTML\QuickForm.php in function call_user_func(array(Dataface_QuickForm Object,save),array(28,1,45,2007-11-05,Save,3,array(3),,edit,0,analisi,0,30,browse,-action=edit&-cursor=0&-table=a)
On line 103 of file C:\xampp\htdocs\dataface\actions\edit.php in function process(array(Dataface_QuickForm Object,save))
On l in C:\xampp\htdocs\dataface\Dataface\QuickForm.php on line 2046

What OS are you using? Linux? Next I will try with OpenSuse 10.3